Point at x=0 is the release point. Red line is trajectory without gravity (or spin). Black line would be trajectory
with gravity and spin. Riseball never gets above red line but it can be higher (larger y) than the y value at x=0.
View attachment 22351
I feel like I have had this conversation about 10 times on here
So if that red line was straight and the ball had spin would it or could it with proper spin, spin rate and velocity crops the plate above where it started.
I say absolutely. Of course at some point spin velocity and gravity effect the ball in a way that causes it to drop.
What say you. ? Because what it seems you’re saying is a ball without spin or proper velocity. Do have that correct. ?
Sent from my iPhone using Tapatalk